Danny Jansen will make history on Monday.

The Boston Red Sox catcher will be the first player in MLB history to play for both teams in the same game as Boston takes on the Toronto Blue Jays.

Jansen began the season with the Blue Jays but was traded ahead of the deadline on July 27. The Red Sox and Toronto faced off on June 26, a game that was ultimately postponed and pushed to this Monday.

Red Sox manager Alex Cora announced Monday that Jansen will substitute in for Reese McGuire at catcher, meaning he will have played for both teams in the same game. Adding to the oddity, Jansen will play catcher during the at-bat that he started back in June.

The game in June was suspended in the bottom of the second inning and Jansen was set to take his first at-bat with the score tied at zero.

In 74 games this season, Jansen has eight homers, 23 RBI and a .219 batting average. Since joining the Red Sox in July, he's improved his numbers, notching a pair of homers, five RBI and a .257 batting average in his first 13 games.

As he faces his former team on Monday, he'll look to prove the Red Sox were the winner of the trade that sent him away from Toronto.

The Red Sox head into next week's series against the Blue Jays looking for a late-season push to ensure a postseason berth. Boston is currently on the outside looking in, but sits just 3.5 games back from a wild-card slot, so a strong ending to the regular season could be enough for them to reach the playoffs for the first time since 2021.